0=4x^2+2x+4

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Solution for 0=4x^2+2x+4 equation: 



0=4x^2+2x+4

We move all terms to the left:

0-(4x^2+2x+4)=0

We add all the numbers together, and all the variables

-(4x^2+2x+4)=0

We get rid of parentheses

-4x^2-2x-4=0

a = -4; b = -2; c = -4;
Δ = b2-4ac
Δ = -22-4·(-4)·(-4)
Δ = -60
Delta is less than zero, so there is no solution for the equation

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